If it's not what You are looking for type in the equation solver your own equation and let us solve it.
X^2+2X-275=0
a = 1; b = 2; c = -275;
Δ = b2-4ac
Δ = 22-4·1·(-275)
Δ = 1104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1104}=\sqrt{16*69}=\sqrt{16}*\sqrt{69}=4\sqrt{69}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{69}}{2*1}=\frac{-2-4\sqrt{69}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{69}}{2*1}=\frac{-2+4\sqrt{69}}{2} $
| 0.17(10,000)-0.06y=0.04(y+10,000) | | 2x-13+3x+4=46 | | (18x2)x5=18x(2x | | 3×14=4x-7 | | -2(5x-2)=28 | | 300+30d=61d+30d | | 22(-4y)+6y=-3 | | 3x^2+59x+50=0 | | -3×14=4x-7 | | 15=-3(5r+6) | | 7x-77=100 | | 0=-5x+2x^2 | | X-7/5=1-x/5 | | 12x^2-8x+104=0 | | √(3x-2)=4-x | | 5x+8=x-4-8x | | 1/3x^2+3x+6=0 | | 0+7b=432 | | 90-x=22x | | -4(6+9d)=28 | | 180-x=22x | | 11y-9y-11=26.10 | | 12x-8=8x+10 | | 3/12x+3=11 | | 180=23x | | 3/1x+3=4-x | | 9x^-9+4x^2=0 | | 3(u+2)+2u=7(u-1) | | (19x-6)=(16x+12) | | -1/6(x-8)+1/2(x+2)=+16 | | 1y÷3-9=12 | | 16-4n=30 |